New Delhi : Starting April 24, Prime Minister Modi will embark on a two-day journey covering almost 5,000 km in various areas of the country in 36 hours, during which he will attend eight programmes and visit seven different cities.
On April 24, the Prime Minister will depart from the national capital for Madhya Pradesh in central India. Following that, he would travel to Kerala in the south, then to the union Territory in the west, before returning to Delhi, authorities said on Saturday.
Officials detailed the Prime Minister’s extensive travel schedule, saying, The PM will begin the journey in the morning of April 24. He will travel around 500 km from Delhi to Khajuraho. He would go from Khajuraho to Rewa to participate in the National Panchayati Raj Day celebrations. Following there, he will return to Khajuraho, covering around 280 km in to-and-fro travel. He would fly from Khajuraho to Kochi, a distance of around 1,700 km, to participate in the Yuvam Conclave.
The Prime Minister will travel from Kochi to Thiruvananthapuram the following morning, covering a distance of approximately 190 kilometres. He will flag off the Vande Bharat Express as well as dedicate and lay the foundation stone for several projects.
He will travel around 1570 miles from here to Silvassa via Surat. He will visit NAMO Medical College and dedicate and set the groundwork for different initiatives, they stated. PM Modi will next proceed to Daman for the opening of the Devka beachfront, after which he would travel 110 miles to Surat.
From Surat, he will travel back to Delhi, adding another 940 km to his travel schedule, they claimed. The Prime Minister will cover a stunning aerial distance of about 5,300 km as part of his jam-packed programme. To put this figure into context, consider the length of India from north to south, which is approximately 3200 kilometres. The time aspect adds to the distance – all of this travel is squeezed into only 36 hours, the officials noted.